#978

One Leader per Category

Each category card must show exactly one most expensive product. If prices tie, the product with the smaller id wins. Fix the report so it returns category and name, one row per category, sorted by category.

Buggy query
SELECT category, name
FROM (
  SELECT category, name,
         RANK() OVER (PARTITION BY category ORDER BY price DESC) rn
  FROM products
) t
WHERE rn = 1
ORDER BY category, name;

Uzorak očekivanog izlaza

Ovako izgleda ispravan odgovor — broj redaka je njegov vlastiti, ne mora se podudarati s tablicama sheme.

namecategory
Lamphome
Mugkitchen
Notebookoffice

Ovdje će se pojaviti rezultat tvog upita